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Mar 16, '08, 7:23 pm
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Fun with math!
Whoever solves the current problem gets to post the next one. If it isn't solved in 24 hours, then it is either a stumper or a thread killer...
Picture a right triangle. The hypotenuse is x. One side is sqrt(a-b) and the other is sqrt(b-a). x=?
__________________
Remember the Persecuted Church.
"on God call thou, thine own are sins, merits are God’s. Punishment to thee is owing, and when reward shall have come, His own gifts He will crown, not thy merits."
-Augustine, Narrations on the Psalms, 71:18 sec 22
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Mar 16, '08, 7:35 pm
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Join Date: September 6, 2006
Posts: 20,362
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Re: Fun with math!
Isn't it the square root of the sum of both sides (not the diagonal)? I remember something like that way back in middle school.
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O Blood and Water which gushed forth from the Heart of Jesus as Font of Mercy for us, I trust in You!
Tiber Swim Team '07-'08
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Mar 16, '08, 7:42 pm
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Banned
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Join Date: February 27, 2008
Posts: 18,047
Religion: Catholic
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Re: Fun with math!
Physically impossible. If a-b is positive, it is impossible for b-a to be positive. Since you cannot take the square root of a negative number, you do not have the length of one side.
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Mar 16, '08, 7:46 pm
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Re: Fun with math!
Quote:
Originally Posted by peregrinus_WA
Physically impossible. If a-b is positive, it is impossible for b-a to be positive. Since you cannot take the square root of a negative number, you do not have the length of one side.
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Thus an "Imaginary Number". (square root of i, I think.)
__________________
O Blood and Water which gushed forth from the Heart of Jesus as Font of Mercy for us, I trust in You!
Tiber Swim Team '07-'08
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Mar 17, '08, 5:56 pm
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Re: Fun with math!
Well if a=b then x=0, but then
x is always zero, regardless of what a and b are.
(sqrt(a-b))^2+(sqrt(b-a))^2 =x
a-b+ b-a = x
a-a+b-b = x
0+ 0 =x
0= x
It's an odd little right triangle, what with an imaginary number for a side!
__________________
Remember the Persecuted Church.
"on God call thou, thine own are sins, merits are God’s. Punishment to thee is owing, and when reward shall have come, His own gifts He will crown, not thy merits."
-Augustine, Narrations on the Psalms, 71:18 sec 22
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Mar 17, '08, 6:13 pm
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Join Date: February 27, 2008
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Re: Fun with math!
Quote:
Originally Posted by Truthstalker
Well if a=b then x=0, but then
x is always zero, regardless of what a and b are.
(sqrt(a-b))^2+(sqrt(b-a))^2 =x
a-b+ b-a = x
a-a+b-b = x
0+ 0 =x
0= x
It's an odd little right triangle, what with an imaginary number for a side!
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I deal in real numbers
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Mar 19, '08, 5:00 pm
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Re: Fun with math!
Quote:
Originally Posted by peregrinus_WA
I deal in real numbers 
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For the case a = b all the numbers are real.
Anyone want another one, or should we just let this thread die?
__________________
Remember the Persecuted Church.
"on God call thou, thine own are sins, merits are God’s. Punishment to thee is owing, and when reward shall have come, His own gifts He will crown, not thy merits."
-Augustine, Narrations on the Psalms, 71:18 sec 22
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Mar 19, '08, 10:07 pm
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Prayer Warrior Radio Club Member Forum Supporter
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Join Date: February 20, 2007
Posts: 860
Religion: Bitter Catholic
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Re: Fun with math!
Quote:
Originally Posted by Truthstalker
For the case a = b all the numbers are real.
Anyone want another one, or should we just let this thread die?
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Was the problem solved? If so, bring on the next one.
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Mar 22, '08, 12:21 pm
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Re: Fun with math!
Quote:
Originally Posted by ABostonCatholic
Was the problem solved? If so, bring on the next one.
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In all cases x=0.
b = -2a is kind of interesting.
Since this wasn't solved, I'll have to think up another fun problem.
Or was it solved?  If p_WA claims his solution was valid, he may post the next problem...
__________________
Remember the Persecuted Church.
"on God call thou, thine own are sins, merits are God’s. Punishment to thee is owing, and when reward shall have come, His own gifts He will crown, not thy merits."
-Augustine, Narrations on the Psalms, 71:18 sec 22
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