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  #1  
Old Mar 16, '08, 7:23 pm
Truthstalker Truthstalker is offline
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Default Fun with math!

Whoever solves the current problem gets to post the next one. If it isn't solved in 24 hours, then it is either a stumper or a thread killer...

Picture a right triangle. The hypotenuse is x. One side is sqrt(a-b) and the other is sqrt(b-a). x=?
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  #2  
Old Mar 16, '08, 7:35 pm
Jennifer G. Jennifer G. is offline
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Default Re: Fun with math!

Isn't it the square root of the sum of both sides (not the diagonal)? I remember something like that way back in middle school.
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  #3  
Old Mar 16, '08, 7:42 pm
peregrinus_WA peregrinus_WA is offline
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Default Re: Fun with math!

Physically impossible. If a-b is positive, it is impossible for b-a to be positive. Since you cannot take the square root of a negative number, you do not have the length of one side.
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  #4  
Old Mar 16, '08, 7:46 pm
Jennifer G. Jennifer G. is offline
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Default Re: Fun with math!

Quote:
Originally Posted by peregrinus_WA View Post
Physically impossible. If a-b is positive, it is impossible for b-a to be positive. Since you cannot take the square root of a negative number, you do not have the length of one side.
Thus an "Imaginary Number". (square root of i, I think.)
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  #5  
Old Mar 17, '08, 5:56 pm
Truthstalker Truthstalker is offline
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Default Re: Fun with math!

Well if a=b then x=0, but then
x is always zero, regardless of what a and b are.

(sqrt(a-b))^2+(sqrt(b-a))^2 =x

a-b+ b-a = x

a-a+b-b = x

0+ 0 =x

0= x

It's an odd little right triangle, what with an imaginary number for a side!
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Remember the Persecuted Church.

"on God call thou, thine own are sins, merits are God’s. Punishment to thee is owing, and when reward shall have come, His own gifts He will crown, not thy merits."
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  #6  
Old Mar 17, '08, 6:13 pm
peregrinus_WA peregrinus_WA is offline
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Default Re: Fun with math!

Quote:
Originally Posted by Truthstalker View Post
Well if a=b then x=0, but then
x is always zero, regardless of what a and b are.

(sqrt(a-b))^2+(sqrt(b-a))^2 =x

a-b+ b-a = x

a-a+b-b = x

0+ 0 =x

0= x

It's an odd little right triangle, what with an imaginary number for a side!
I deal in real numbers
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  #7  
Old Mar 19, '08, 5:00 pm
Truthstalker Truthstalker is offline
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Default Re: Fun with math!

Quote:
Originally Posted by peregrinus_WA View Post
I deal in real numbers
For the case a = b all the numbers are real.

Anyone want another one, or should we just let this thread die?
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Remember the Persecuted Church.

"on God call thou, thine own are sins, merits are God’s. Punishment to thee is owing, and when reward shall have come, His own gifts He will crown, not thy merits."
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  #8  
Old Mar 19, '08, 10:07 pm
ABostonCatholic ABostonCatholic is offline
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Default Re: Fun with math!

Quote:
Originally Posted by Truthstalker View Post
For the case a = b all the numbers are real.

Anyone want another one, or should we just let this thread die?
Was the problem solved? If so, bring on the next one.
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  #9  
Old Mar 22, '08, 12:21 pm
Truthstalker Truthstalker is offline
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Default Re: Fun with math!

Quote:
Originally Posted by ABostonCatholic View Post
Was the problem solved? If so, bring on the next one.
In all cases x=0.

b = -2a is kind of interesting.

Since this wasn't solved, I'll have to think up another fun problem.
Or was it solved? If p_WA claims his solution was valid, he may post the next problem...
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Remember the Persecuted Church.

"on God call thou, thine own are sins, merits are God’s. Punishment to thee is owing, and when reward shall have come, His own gifts He will crown, not thy merits."
-Augustine, Narrations on the Psalms, 71:18 sec 22
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